Title
views::concat(r) is well-formed when r is an output_range
Status
ready
Section
[range.concat.overview]
Submitter
Hewill Kang

Created on 2024-04-27.00:00:00 last changed 1 month ago

Messages

Date: 2024-05-08.10:36:29

Proposed resolution:

This wording is relative to N4981.

  1. Modify [range.concat.overview] as indicated:

    -2- The name views::concat denotes a customization point object ([customization.point.object]). Given a pack of subexpressions Es..., the expression views::concat(Es...) is expression-equivalent to

    1. (2.1) — views::all(Es...) if Es is a pack with only one element whose type models input_range,

    2. (2.2) — otherwise, concat_view(Es...).

Date: 2024-05-15.00:00:00

[ 2024-05-08; Reflector poll ]

Set status to Tentatively Ready after seven votes in favour during reflector poll.

Date: 2024-04-27.00:00:00

Currently, views::concat will return views::all(r) when it takes only one argument, which only requires that the type of r models viewable_range which includes output_range:

std::vector<int> v;
auto r = std::views::counted(std::back_inserter(v), 3);
auto c = std::views::concat(r); // well-formed

Since concat_view requires all ranges to be input_range, this seems inconsistent. We should reject the above just like views::zip_transform still requires F to be move_constructible in the case of an empty pack.

History
Date User Action Args
2024-05-08 10:36:29adminsetmessages: + msg14125
2024-05-08 10:36:29adminsetstatus: new -> ready
2024-04-28 07:49:41adminsetmessages: + msg14085
2024-04-27 00:00:00admincreate