Proposed resolution:

This wording is relative to N4606.

1. Modify [reverse.iter.opref] as indicated:

   constexpr pointer operator->() const;
   

   -1- Returns: addressof(operator*()).Effects: If Iterator is a pointer type, as if by:

   Iterator tmp = current;
   return --tmp;
   

   Otherwise, as if by:

   Iterator tmp = current;
   --tmp;
   return tmp.operator->();
   

[ Issues processing Telecon 2016-10-7 ]

Set status to Duplicate

Duplicate: 1052

std::reverse_iterator<Iterator>::operator->() is specified to call addressof(operator*()), but it returns iterator_traits<Iterator>::pointer, which may be a fancy pointer type from which no conversion from T* is possible. It should instead delegate to the underlying iterator's operator->().