Title
std::move in std::accumulate and other algorithms
Status
resolved
Section
[numeric.ops]
Submitter
Chris Jefferson

Created on 2011-01-01.00:00:00 last changed 77 months ago

Messages

Date: 2017-11-15.00:00:00

[ 2017-11-11, Albuquerque ]

This was resolved by the adoption of P0616r0.

Date: 2017-06-05.20:39:07

[ 2011 Bloomington ]

Moved to NAD Future. This would be a larger change than we would consider for a simple TC. 2017-02 in Kona, LEWG responds

Like the goal.

What is broken by adding std::move() on the non-binary-op version?

A different overload might be selected, and that would be a breakage. Is it breakage that we should care about?

We need to encourage value semantics.

Need a paper. What guidance do we give?

Use std::reduce() (uses generalized sum) instead of accumulate which doesn’t suffer it.

Inner_product and adjacent_difference also. adjacent_difference solves it half-way for “val” object, but misses the opportunity for passing acc as std::move(acc).

2017-06-02 Issues Telecon

Ville to encourage Eelis to write a paper on the algorithms in <numeric>, not just for accumulate.

Howard pointed out that this has already been done for the algorithms in <algorithm>

Status to Open; Priority 3

Date: 2011-01-01.00:00:00

The C++0x draft says std::accumulate uses: acc = binary_op(acc, *i).

Eelis van der Weegen has pointed out, on the libstdc++ mailing list, that using acc = binary_op(std::move(acc), *i) can lead to massive improvements (particularly, it means accumulating strings is linear rather than quadratic).

Consider the simple case, accumulating a bunch of strings of length 1 (the same argument holds for other length buffers). For strings s and t, s+t takes time length(s)+length(t), as you have to copy both s and t into a new buffer.

So in accumulating n strings, step i adds a string of length i-1 to a string of length 1, so takes time i.

Therefore the total time taken is: 1+2+3+...+n = O(n2)

std::move(s)+t, for a "good" implementation, is amortized time length(t), like vector, just copy t onto the end of the buffer. So the total time taken is:

1+1+1+...+1 (n times) = O(n). This is the same as push_back on a vector.

I'm trying to decide if this implementation might already be allowed. I suspect it might not be (although I can't imagine any sensible code it would break). There are other algorithms which could benefit similarly (inner_product, partial_sum and adjacent_difference are the most obvious).

Is there any general wording for "you can use rvalues of temporaries"?

The reflector discussion starting with message c++std-lib-29763 came to the conclusion that above example is not covered by the "as-if" rules and that enabling this behaviour would seem quite useful.

History
Date User Action Args
2017-12-20 03:35:43adminsetmessages: + msg9600
2017-12-20 03:35:43adminsetstatus: open -> resolved
2017-06-05 15:41:21adminsetstatus: lewg -> open
2014-11-24 15:11:58adminsetstatus: nad future -> lewg
2011-08-17 12:17:15adminsetmessages: + msg5861
2011-08-17 12:17:15adminsetstatus: new -> nad future
2011-01-01 00:00:00admincreate