Notes from 4/02 meeting:

There is a problem in that class-or-namespace-name does not include typedef names for cv-qualified class types. See 9.2.4 [dcl.typedef] paragraph 4:

Argument and text removed from proposed resolution (October 2002):

9.2.4 [dcl.typedef] paragraph 5:

Here's a good question: in this example, should X be used as a name-for-linkage-purposes (FLP name)?

  typedef class { } const X;

Because a type-qualifier is parsed as a decl-specifier, it isn't possible to declare cv-qualified and cv-unqualified typedefs for a type in a single declaration. Also, of course, there's no way to declare a typedef for the cv-unqualified version of a type for which only a cv-qualified version has a name. So, in the above example, if X isn't used as the FLP name, then there can be no FLP name. Also note that a FLP name usually represents a parameter type, where top-level cv-qualifiers are usually irrelevant anyway.

Data points: for the above example, Microsoft uses X as the FLP name; GNU and EDG do not.

My recommendation: for consistency with the direction we're going on this issue, for simplicity of description (e.g., "the first class-name declared by the declaration"), and for (very slightly) increased utility, I think Microsoft has this right.

If the typedef declaration defines an unnamed class type (or enum type), the first typedef-name declared by the declaration to be have that class type (or enum type) or a cv-qualified version thereof is used to denote the class type (or enum type) for linkage purposes only (6.6 [basic.link]). [Example: ...