It is not clear whether the following example is well-formed or not:

    template<class T> struct identity { typedef T type; };

    template<class T, class C>
    void f(T C::*, typename identity<T>::type*){}

    struct X { void f() {}; };

    int main() { f(&X::f, 0); }

The null pointer conversion required for the second parameter of f is not one of the ones permitted by 13.10.3.2 [temp.deduct.call] paragraph 4, but it's unclear whether that list should apply to parameters with nondeduced types or not. 13.10.2 [temp.arg.explicit] paragraph 6 is explicit that

Implicit conversions (7.3 [conv]) will be performed on a function argument to convert it to the type of the corresponding function parameter if the parameter type contains no template-parameters that participate in template argument deduction.

However, this statement appears in a section dealing with explicitly-specified template arguments, so its applicability to nondeduced contexts in general is not clear.

Implementations disagree on the handling of this example.