Created on 2009-10-20.00:00:00 last changed 179 months ago
[Voted into WP at March, 2010 meeting as part of document N3079.]
Proposed resolution (February, 2010):
Change 9.4.5 [dcl.init.list] paragraph 3 as follows:
List-initialization of an object or reference of type T is defined as follows:
If the initializer list has no elements and T is a class type with a default constructor, the object is value-initialized.
Otherwise, if the initializer list has no elements and T is an aggregate, the initializer list is used to initialize each of the members of T. [Example:
struct A { A(std::initializer_list<int>); // #1 }; struct B { A a; }; B b { }; // OK, uses #1 B b { 1 }; // error—end example]
IfOtherwise, if T is an aggregate......
[Example:
struct S { S(std::initializer_list<double>); // #1 S(std::initializer_list<int>); // #2 S(); // #3 // ... }; S s1 = { 1.0, 2.0, 3.0 }; // invoke #1 S s2 = { 1, 2, 3 }; // invoke #2 S s3 = { }; // invoke #3 (for value-initialization; see above)—end example]
It should always be possible to use the new brace syntax to value-initialize an object. However, the current rules make the following example ill-formed because of ambiguity:
struct S { S(); S(std::initializer_list<int>); S(std::initializer_list<double>); }; S s{}; // Ambiguous initializer-list constructor reference, // not value initialization.
History | |||
---|---|---|---|
Date | User | Action | Args |
2010-03-29 00:00:00 | admin | set | messages: + msg2714 |
2010-03-29 00:00:00 | admin | set | status: review -> cd2 |
2010-02-16 00:00:00 | admin | set | messages: + msg2545 |
2010-02-16 00:00:00 | admin | set | status: drafting -> review |
2009-10-20 00:00:00 | admin | create |