Notes from the October, 2009 meeting:

The eventual resolution of this issue should take into account the template parameter scope introduced by the resolution of issue 481.

[Accepted at the November, 2020 meeting as part of paper P1787R6 and moved to DR at the February, 2021 meeting.]

In an example like,

    struct Y {};

    template <typename T>
    struct X : public virtual Y { };

    template <typename T>
    class A : public X<T> {
      template <typename S>
      A (S)
        : S ()
      {
      }
    };

    template A<int>::A (Y);

Should S be found? (S is a dependent name, so if it resolves to a base class type in the instantiated template, it should satisfy the requirements.) All the compilers I tried allowed this example, but 11.9.3 [class.base.init] paragraph 2 says,

Names in a mem-initializer-id are looked up in the scope of the constructor's class and, if not found in that scope, are looked up in the scope containing the constructor's definition.

The name S is not declared in those scopes.

Mike Miller: Here's another example that is accepted by most/all compilers but not by the current wording:

    namespace N {
      struct B { B(int); };
      typedef B typedef_B;
      struct D: B {
        D();
      };
    }

    N::D::D(): typedef_B(0) { }

Except for the fact that the constructor function parameter names are ignored (see paragraph 7), what the compilers seem to be doing is essentially ordinary unqualified name lookup.