(From submission #475.)

Consider:

  void foo () {
    auto f = [i = 5] () { int i; return 0; };
  }

Before P2579R0 and P2036R3, this was ill-formed, because the capture inhabited the same scope as int i. Subclause 6.4.3 [basic.scope.block] paragraph 2 relies on the "parent" scope:

If a declaration that is not a name-independent declaration and whose target scope is the block scope S of a

• compound-statement of a lambda-expression, function-body, or function-try-block,
• substatement of a selection or iteration statement that is not itself a selection or iteration statement, or
• handler of a function-try-block

potentially conflicts with a declaration whose target scope is the parent scope of S, the program is ill-formed.

However, after P2579R0, the init-capture inhabits the lambda scope (6.4.5 [basic.scope.lambda]), which is the parent of the parameter scope (6.4.4 [basic.scope.param]), which is the parent of the compound-statement scope, thus the provision does not apply.

As observed in issue 2965, there is no a template parameter scope (6.4.9 [basic.scope.temp]) for a generic lambda:

  auto f = [i = 5] <int N> () { int i; return 0; };

Possible resolution:

Change in 6.4.3 [basic.scope.block] paragraph 2 as follows, adding bullets:

If a declaration that is not a name-independent declaration and whose target scope is the block scope S of a

• compound-statement of a lambda-expression, function-body, or function-try-block,
• substatement of a selection or iteration statement that is not itself a selection or iteration statement, or
• handler of a function-try-block

potentially conflicts with a declaration whose target scope is

• the parent scope of S or,
• if S is the block scope of a compound-statement of a lambda-expression, the nearest enclosing lambda scope of S,

the program is ill-formed.