Created on 1997-09-25.00:00:00 last changed 330 months ago
I understand that the lvalue-to-rvalue conversion was removed in London. I generally agree with this, but it means that ?: needs to be fixed:
Given:
bool test; Integer a, b; test ? a : b;What builtin do we use? The candidates are
operator ?:(bool, const Integer &, const Integer &) operator ?:(bool, Integer, Integer)which are both perfect matches.
(Not a problem in the C++11 FDIS, but misleading.)
Rationale: The description of the conditional operator in 7.6.16 [expr.cond] handles the lvalue case before the prototype is considered.
History | |||
---|---|---|---|
Date | User | Action | Args |
1997-09-25 00:00:00 | admin | create |