Title
Abstract class return type in decltype operand
Status
dup
Section
7.6.1.3 [expr.call]
Submitter
Mike Miller

Created on 2014-10-27.00:00:00 last changed 121 months ago

Messages

Date: 2014-11-15.00:00:00

Rationale (November, 2014):

This issue is a duplicate of issue 1646.

Date: 2022-11-20.07:54:16

According to 7.6.1.3 [expr.call] paragraph 11, when a function call is the operand of a decltype-specifier,

a temporary object is not introduced for the prvalue. The type of the prvalue may be incomplete. [Note: as a result, storage is not allocated for the prvalue and it is not destroyed; thus, a class type is not instantiated as a result of being the type of a function call in this context. This is true regardless of whether the expression uses function call notation or operator notation (12.2.2.3 [over.match.oper]). —end note] [Note: unlike the rule for a decltype-specifier that considers whether an id-expression is parenthesized (9.2.9.3 [dcl.type.simple]), parentheses have no special meaning in this context. —end note]

This relaxation of requirements on the return type of a function does not mention abstract classes, so presumably the following example is ill-formed:

   struct Abstract {
     virtual ~Abstract() = 0;
   };

   template<class T> T func();

   typedef decltype(func<Abstract>()) type;

However, there is implementation variance on the treatment of the last line.

History
Date User Action Args
2014-11-24 00:00:00adminsetmessages: + msg5298
2014-10-27 00:00:00admincreate