Created on 2010-08-02.00:00:00 last changed 131 months ago
[Voted into the WP at the November, 2010 meeting as paper N3218.]
It is not clear how overload resolution is performed inside the body of a constexpr function. In particular, if the function is invoked with parameters such that an expression evaluates to an integral 0, does that make the expression eligible for the null pointer conversion and thus potentially select a different overloaded function than in invocations in which the expression has a non-zero value? (Suggested answer: no.)
| History | |||
|---|---|---|---|
| Date | User | Action | Args |
| 2014-03-03 00:00:00 | admin | set | status: fdis -> c++11 |
| 2011-04-10 00:00:00 | admin | set | status: dr -> fdis |
| 2011-02-28 00:00:00 | admin | set | status: drafting -> dr |
| 2010-10-18 00:00:00 | admin | set | status: ready -> drafting |
| 2010-08-23 00:00:00 | admin | set | messages: + msg2772 |
| 2010-08-02 00:00:00 | admin | create | |